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01-202402-G22-1291审稿意见与作者答复 点击下载(558KB)01-202402-G22-1291审稿意见与作者答复
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取值 $ c_{\text{F}}^{\text{c}} < c_{{\text{Fc}}}^{\text{c}} $
$ \tilde P < {\tilde P_{\text{c}}} $$ c_{\text{F}}^{\text{c}} \geqslant c_{{\text{Fc}}}^{\text{c}} $
$ \tilde P < {\tilde P_{\text{c}}} $$ c_{\text{F}}^{\text{c}} \geqslant c_{{\text{Fc}}}^{\text{c}} $
$ \tilde P \geqslant {\tilde P_{\text{c}}} $$ c_{\text{F}}^{\text{c}} < c_{{\text{Fc}}}^{\text{c}} $
$ \tilde P \geqslant {\tilde P_{\text{c}}} $$ \lambda $ $ {\lambda ^{\text{e}}} $ $ {\lambda ^{\text{e}}} $ $ {\lambda ^{\text{e}}} + {\lambda ^{\text{p}}}(c_{\text{F}}^{\text{c}}) $ $ {\lambda ^{\text{e}}} + {\lambda ^{\text{p}}}(c_{\text{F}}^{\text{c}}) $ $ {\lambda ^{\text{c}}} $ 0 $ {\lambda ^{\text{c}}} $ $ {\lambda ^{\text{c}}} $ 0 -
$\lambda _1^{\text{p}}$ $\lambda _2^{\text{p}}$ $\lambda _3^{\text{p}}$ ${\lambda ^{\text{c}}}$ ${\lambda ^{\text{e}}}$ 0.0105 -0.147 0.0099 1/0.09 0.014 $ \varepsilon _{\text{p}}^{\text{c}} $ ${\varepsilon _{{\text{Hmax}}}}$ ${\tilde P_{{\text{ref}}}}$/kPa ${\tilde P_{\text{c}}}(0)$/kPa ${K_{{\text{RS}}}}$/GPa -0.08 0.02 5 75 20